Question

I’m using a bit of code that I found on the web to manufacture objects. It allows me to organize objects into namespaces, and keeps my code pretty readable.

var TEST = {};

//The next two lines is the stuff that I found on the web. I think I 
//basically understand what's going on here, but maybe I'm implementing it 
//incorrectly?
TEST.testObj = function () { this.initialize.apply(this, arguments); };
TEST.testObj.prototype = {

    a: null,
    b: [],

    initialize: function(a) {

        this.a = a;
        this.b[0] = a;
    }

}


t1 = new TEST.testObj(1);
t2 = new TEST.testObj(2);

alert(t1.a + ', ' + t2.a);
alert(t1.b + ', ' + t2.b);

So, basically t1.a, a primitive, retains it’s value when t2 is instantiated. But t1.b changes. It seems like both instances are simply referencing a single array, but creating unique primitives.

Answer 1

If you are fuzzy about prototype inheritance, make sure you read up on it – it will help you reason about this problem. In essence, an object inherits all properties of its prototype, but an object’s own properties has higher precedence than those of its prototype. In your example, TEST.testObj.prototype is the prototype of both t1 and t2. Thus, both t1 and t2 inherit its properties.

When the Test.testObj constructor is called, it then calls the initialize method, which then sets the object’s a property to the passed-in parameter. This operation will create an a property on the object itself (it’s own property), this will override the inherited a property on Test.testObj.prototype. Thus, each time a constructor is called, the new object will get its own a property.

The second statement in initialize

this.b[0] = a;

is different in nature. It first looks up property b on the object. Since it is not found on the object itself, it goes up to its prototype Test.testObject.prototype and finds it there. Now, having a handle on the array object, it then modifies its zeroth element. As you can see, each time the constructor gets called, this same array will be modified.