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Home/ Questions/Q 7759595
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T13:40:13+00:00 2026-06-01T13:40:13+00:00

I’m using a form as described here to upload a file to a Youtube

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I’m using a form as described here to upload a file to a Youtube account. Like this:

<form action="<?=$YTurl ?>?nexturl=http://localhost/update-video.php" method="post" enctype="multipart/form-data">
    <input id="file" type="file" name="file"/>
    <input type="hidden" name="token" value="<?=$YTtoken ?>"/>
    <input type="hidden" name="test" value="testvalue1234"/>
    <input type="submit" value="go" />
</form>

But I’m planning to have more fields on the form and since the action is set to YouTube’s server I can’t process the remaining fields. Does anyone has a workaround for this? I’d expect YT to let me add custom parameters and kindly posting them back to me on the callback specified with nexturl.

Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T13:40:14+00:00Added an answer on June 1, 2026 at 1:40 pm

    I finally ended up sending the other form fields via AJAX before submitting the form. I also identify the video with a session id hash to be sure it’s being stored in the proper record. Here is the code in case it helps somebody (wrapped up into jquery.validate.js):

    <script type="text/javascript">
        $(document).ready(function(){
            $("form").validate({
                rules: { ... },
                messages: { ... },
                submitHandler: function (form) {
                    if ($('#video_file').val()) {
                        var data = {};
                        $('input').each(function() {
                            data[$(this).attr('name')] = $(this).val();
                        });
                        $.ajax({
                            url: 'process.php', dataType: 'json', type: 'POST', data: data,
                            success: function(response) {
                                if (response.status == '200') {
                                    url = '<?=$tokenArray['url']?>?nexturl=http://localhost/update-video.php?hash=' + response.sid;
                                    $(form).attr('action', url);                                        
                                    form.submit();
                                }
                            }
                        });
                    } else if ($('#video_url').val()) {
                        form.submit();
                    }
                }
            });
    
        });
    </script>
    
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