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Home/ Questions/Q 6318159
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T15:36:31+00:00 2026-05-24T15:36:31+00:00

I’m using a form to upload files into a specific upload folder. Now, in

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I’m using a form to upload files into a specific upload folder.
Now, in my local development environment, the local folder is harcoded in a variable like this

$destination = 'c:/public_html/discography/artwork/';

Once the script is completed and ready to be moved in the live environment, the upload folder will be

$destination = '/home/my_name/public_html/discography/artwork/';

My question is the following:
Right now, both variables are hard coded. How do i make it so depending on the environment, the correct path is selected?

If possible, i’d like it to be in a define statement, so i can use it anywhere in my script:

define('UPLOAD_ARTWORK', ????);

local:

$destination = 'c:/public_html/discography/artwork/';
$move = move_uploaded_file($_FILES['artwork']['tmp_name'], $destination.$_FILES['artwork']['name']);

live:

$destination = '/home/my_name/public_html/discography/artwork/';
$move = move_uploaded_file($_FILES['artwork']['tmp_name'], $destination.$_FILES['artwork']['name']);

wishing for

define('UPLOAD_ARTWORK', ????);
$move = move_uploaded_file($_FILES['artwork']['tmp_name'], UPLOAD_ARTWORK.$_FILES['artwork']['name']);

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T15:36:31+00:00Added an answer on May 24, 2026 at 3:36 pm

    Your on the right path. All you need is some way to determine whether the script is being run locally or on the live server. This could be a subdomain if you’re using something like dev.example.com or an ip address ala 127.0.0.1. Then you could write it like this.

    switch($_SERVER['HTTP_HOST']){
        case "dev.example.com":
            define('UPLOAD_ARTWORK','c:/public_html/discography/artwork/');
            break;
        default:
            define('UPLOAD_ARTWORK','/home/my_name/public_html/discography/artwork/');
    }
    $move = move_uploaded_file($_FILES['artwork']['tmp_name'], UPLOAD_ARTWORK.$_FILES['artwork']['name']);
    
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