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Home/ Questions/Q 1076121
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:22:01+00:00 2026-05-16T21:22:01+00:00

I’m using a simple regular expression to match on the start of words, using

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I’m using a simple regular expression to match on the start of words, using the word boundary matcher, like

/(\b)rice/

will match on “years of rice and salt” but not “maurice ravel” and so on.

However, I’m finding a ! at the start of the string is negating the word boundary matcher. So the string “!!” is matching on “some text!!”.

Anyone know why this would be happening? Haven’t seen that it’s a special character.

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:22:02+00:00Added an answer on May 16, 2026 at 9:22 pm

    There is a word boundary between t and ! because t is a word character and ! is not a word character. There is nothing special about ! apart from you assumed it was a word character, but it is not.

    Since you are not dealing with “words” the word boundary is not what you want. Instead you could use a lookbehind assertion and check if the previous character is whitespace, start of line, or any other character you wish to allow as your separator. Note that not all regex engines support lookbehind assertions.

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