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Home/ Questions/Q 7652289
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T11:43:46+00:00 2026-05-31T11:43:46+00:00

I’m using a threading library given to me at school and having trouble understanding

  • 0

I’m using a threading library given to me at school and having trouble understanding how to pass a reference of an array of pointers to a method, or rather, I’m having trouble de-referencing and using the pointer array.

The situation that I (believe I) understand is this:

int main(void)
{
    Foo* bar = new Foo();

    // Passing instance of Foo pointer by reference 
    CThread *myThread = new CThread(MyFunction, ACTIVE, &bar);

    return 0;
}

UINT __stdcall MyFunction(void *arg)
{
    Foo* bar = *(Foo*)(arg); 

    return 0;
}

I’m creating a pointer to a Foo object and passing it by reference to a thread running MyFunction, which accepts a void pointer as its argument. MyFunction then casts “arg” to a Foo pointer and de-references it to get the original object.

My problem arises when I want to pass an array of Foo pointers instead of just one:

int main(void)
{
    Foo* barGroup[3] = 
    {
        new Foo(),
        new Foo(),
        new Foo()
    };

    // Passing instance of Foo pointer by reference 
    CThread *myThread = new CThread(MyFunction, ACTIVE, &barGroup);

    return 0;
}

UINT __stdcall MyFunction(void *arg)
{
    // This is wrong; how do I do this??
    Foo* barGroup[3] = *(Foo[]*)(arg); 

    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-31T11:43:47+00:00Added an answer on May 31, 2026 at 11:43 am

    Replace MyFunction(&barGroup); with MyFunction(barGroup); (thus passing a pointer to the first element instead of a pointer to the entire array) and use a nested pointer:

    Foo** barGroup = (Foo**)(arg); 
    

    Then you can simply use barGroup[0], barGroup[1] and barGroup[2].

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