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Home/ Questions/Q 869831
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:22:25+00:00 2026-05-15T10:22:25+00:00

I’m using an algorithm to generate quads. These become outlines. The algorithm is: void

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I’m using an algorithm to generate quads. These become outlines. The algorithm is:

 void OGLENGINEFUNCTIONS::GenerateLinePoly(const std::vector<std::vector<GLdouble>> &input,
     std::vector<GLfloat> &output, int width)
 {

     output.clear();
     if(input.size() < 2)
     {
         return;
     }
     int temp;
     float dirlen;
     float perplen;
     POINTFLOAT start;
     POINTFLOAT end;
     POINTFLOAT dir;
     POINTFLOAT ndir;
     POINTFLOAT perp;
     POINTFLOAT nperp;

     POINTFLOAT perpoffset;
     POINTFLOAT diroffset;

     POINTFLOAT p0, p1, p2, p3;

     for(unsigned int i = 0; i < input.size() - 1; ++i)
     {

         start.x = static_cast<float>(input[i][0]);
         start.y = static_cast<float>(input[i][1]);

         end.x = static_cast<float>(input[i + 1][0]);
         end.y = static_cast<float>(input[i + 1][1]);

         dir.x = end.x - start.x;
         dir.y = end.y - start.y;

         dirlen = sqrt((dir.x * dir.x) + (dir.y * dir.y));

         ndir.x = static_cast<float>(dir.x * 1.0 / dirlen);
         ndir.y = static_cast<float>(dir.y * 1.0 / dirlen);

         perp.x = dir.y;
         perp.y = -dir.x;

         perplen = sqrt((perp.x * perp.x) + (perp.y * perp.y));

         nperp.x = static_cast<float>(perp.x * 1.0 / perplen);
         nperp.y = static_cast<float>(perp.y * 1.0 / perplen);

         perpoffset.x = static_cast<float>(nperp.x * width * 0.5);
         perpoffset.y = static_cast<float>(nperp.y * width * 0.5);

         diroffset.x = static_cast<float>(ndir.x * 0 * 0.5);
         diroffset.y = static_cast<float>(ndir.y * 0 * 0.5);

            // p0 = start + perpoffset - diroffset
             //p1 = start - perpoffset - diroffset
             //p2 = end + perpoffset + diroffset
            // p3 = end - perpoffset + diroffset 

         p0.x = start.x + perpoffset.x - diroffset.x;
         p0.y = start.y + perpoffset.y - diroffset.y;

         p1.x = start.x - perpoffset.x - diroffset.x;
         p1.y = start.y - perpoffset.y - diroffset.y;

             p2.x = end.x + perpoffset.x + diroffset.x;
             p2.y = end.y + perpoffset.y + diroffset.y;

             p3.x = end.x - perpoffset.x + diroffset.x;
             p3.y = end.y - perpoffset.y + diroffset.y;




         output.push_back(p2.x);
         output.push_back(p2.y);
         output.push_back(p0.x);
         output.push_back(p0.y);
         output.push_back(p1.x);
         output.push_back(p1.y);
         output.push_back(p3.x);
         output.push_back(p3.y);

     }
 }

The problem is that there are then gaps as seen here:
http://img816.imageshack.us/img816/2882/eeekkk.png

There must be a way to fix this. I see a pattern but I just cant figure it out. There must be a way to fill the missing inbetweens.
Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:22:25+00:00Added an answer on May 15, 2026 at 10:22 am

    EDIT: See my other answer.

    Add a triangle connecting the “outside” (check the sign of the 2D ‘cross product‘) vertexes with the center joint vertex.

    If you want to get fancier you can do a 2D slerp to get a more rounded outer join, though this does cost correspondingly more triangles.

    Also, if you’re going to use lines that wide and so finely subdivided you might try simplifying them first to reduce overdraw/polycount.

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