Question

I’m using array_unique to remove duplicates from an array, but even though the counter is right, and the number of the elements is right, some of its elements are displayed as undefined!

$varietals=array_unique($varietals1);

$countVarietals = count($varietals);

I’m listing results with jquery

var Varietal = data.Varietal;
var countVarietal = data.countVarietal;
//  alert(countVarietal);
$("#selectVarietal").html("");
for(var i = 0; i < countVarietal; i++){

    $("#selectVarietal").append("<label><input type='checkbox' class='wineTypeCheck'  name='Varietal' value='"+Varietal[i]+"' />"+Varietal[i]+"</label><br />");
}       

Anybody familiar with this?
thank u in advance!

Answer 1

  a = array("one", "two", "two", "three")
  a = array_unique(a);
  /* will lead to:
  a[0] = "one"
  a[1] = "two"
  a[3] = "three"
  */
  a = array_values(a);

   /* Now we've got:
  a[0] = "one"
  a[1] = "two"
   a[2] = "three"
  */

thus I needed to add array_values(), in order to close the gap

    $varietals=array_values(array_unique($varietals1));

source: http://php.net/manual/en/function.array-unique.php