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Home/ Questions/Q 748377
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:18:49+00:00 2026-05-14T14:18:49+00:00

I’m using Clojure, so this is in the context of Java regexes. Here is

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I’m using Clojure, so this is in the context of Java regexes.

Here is an example string:

{:a "ab,cd, efg", :b "ab,def, egf,", :c "Conjecture"}

The important bits are the commas after each string. I’d like to be able to replace them with newline characters with Java’s replaceAll method. A regex that will match any comma that is not surrounded by quotes will do.

If I’m not coming across well, please ask and I’ll be happily to clarify anything.

edit: sorry for the confusion in the title. I haven’t been awake very long.

String: {:a "ab, cd efg",} <– In this example, the comma at the end would be matched, but the ones inside the quote would not.

String: {:a 3, :b 3,} <– Every single comma matches.

String {:a "abcd,efg" :b "abcedg,e"} <– Every single comma doesn’t match.

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:18:50+00:00Added an answer on May 14, 2026 at 2:18 pm

    The regex:

    ,\s*(?=([^"]*"[^"]*")*[^"]*$)
    

    Matches:

    {:a "ab,cd, efg", :b "ab,def, egf,", :c "Conjecture"}
                    ^                  ^
                    ^                  ^
    

    and:

    {:a "ab, cd efg",}
                    ^
                    ^
    

    and does not match a comma in:

    {:a "abcd,efg" :b "abcedg,e"}
    

    But when escaped quotes can appear, like so:

    {:a "ab,\" cd efg",} // only the last comma should match
    

    then a regex solution won’t work.

    A brief explanation of the regex:

    ,            # match the character ','
    \s*          # match a whitespace character: [ \t\n\x0B\f\r] and repeat it zero or more times
    (?=          # start positive look ahead
      (          #   start capture group 1
        [^"]*    #     match any character other than '"' and repeat it zero or more times
        "        #     match the character '"'
        [^"]*    #     match any character other than '"' and repeat it zero or more times
        "        #     match the character '"'
      )*         #   end capture group 1 and repeat it zero or more times
      [^"]*      #   match any character other than '"' and repeat it zero or more times
      $          #   match the end of the input
    )            # end positive look ahead
    

    In other words: match any comma that has zero, or an even number of quotes ahead of it (until the end of the string).

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