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Editorial Team
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Asked: 2026-05-24T21:17:37+00:00

I’m using Crossslide image gallery, and here is my image javascript file code which

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I’m using Crossslide image gallery, and here is my image javascript file code which is connected to the index.php (which only has an ad_image div for the gallery)

$(function() {
$('#ad_image').crossSlide({                     
  sleep: 5,
  fade: 2
}, [
  { src: 'images/slideshow/1.jpg' },
  { src: 'images/slideshow/2.jpg' },
  { src: 'images/slideshow/3.jpg' }
])
});

I set up a database table screen_image in phpmyadmin, and would like to get images(eg 1.jpg, 2.jpg) from database rather than from the code above. The reason for doing so is that I am planning to build a backend/admin for it later on.

How do I go about connecting the Javascript file above to database using php? I’m new to this php/backend so a bit detailed explanation/coding would be very helpful.

Thank you for your help.

Regards
S:)

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1 Answer

  1. Editorial Team

    Suppose this is your image.php page

    <?php 
$link = mysql_connect("localhost", "username", "password");
mysql_select_db("display");
?>

<html>
<head>
you can link all your javascript files here
<script type="text/javascript" src="you js file name with relative path"></script>
<script type="text/javascript" src="you js file name with relative path"></script>
<script type="text/javascript">

    this code will go like this in this script tag

        $(function() {
    $('#ad_image').crossSlide({                     
      sleep: 5,
      fade: 2
    }, [<?php

          $arr = array();
          $result = mysql_query('SELECT * FROM `screen_image`');
          while($row=mysql_fetch_assoc($result)
          {
               $arr="{ src: 'images/slideshow/".$row['Your image field']."' }";
          }
           echo implode(',',$arr);
        ?>

    ])
    });
</script>
<body>
</body>
</html>
<?php mysql_close($link); ?>
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