Question

I’m using dynamic forms in my project, the input field’s id increments by 1 each time a new field set is called:

 <input type="text" id="billing_id1" />
 <input type="text" id="billing_id2" />

In the processor how would I go about submitting all data, because the following code is only submitting the first field set…

processor:

$billing_id = empty($_POST['billing_id']) ? die ("ERROR: Billing ID was not submitted") : mysql_escape_string($_POST['billing_id']);

$connection = mysql_connect($mysql_server, $mysql_user, $mysql_pass) or die("Could not connect to database");

mysql_select_db($mysql_db) or ("Unable to select database");

$query = "INSERT INTO customer_contacts (billing_id) VALUES ('$billing_id')";

$result = mysql_query($query) or die ("ERROR: $query. ".mysql_error());

Hope someone can help, thanks

Answer 1

If you use square brackets instead:

<input type="text" id="billing_ids[]" />
<input type="text" id="billing_ids[]" />

You’ll get an array instead of individual values

// $billing_ids == array('val1', 'val2');
foreach($billing_ids AS $id) {
    $query = "INSERT INTO customer_contacts (billing_id) VALUES ('$id')";
    $result = mysql_query($query) or die ("ERROR: $query. ".mysql_error());
}