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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:52:14+00:00 2026-05-12T17:52:14+00:00

Im using following code: TreeNode i = treeView1.SelectedNode; RefillTree(); //clears the tree and rebuilt

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Im using following code:

TreeNode i = treeView1.SelectedNode;

RefillTree(); //clears the tree and rebuilt it again.

treeView1.SelectedNode=i;

However, SelectedNode still remains null, however “i” is correctly referencing.

I would need to select and expand particular node automatically after tree refresh.

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:52:15+00:00Added an answer on May 12, 2026 at 5:52 pm

    What does “RefillTree” do exactly? If it removes the Node referenced by ‘i’, then I would expect that setting the SelectedNode property to a node that does not exist in the control would have no effect.

    EDIT:

    I can almost guarantee that you are clearing the control and creating new nodes to fill it with. It does not matter if these new nodes contain the same data, SelectedNode looks for object equality and it doesn’t find a match. for example, this code reproduces your problem:

    treeView1.nodes.Add( new TreeNode( "Node 1" ) );
    treeView1.nodes.Add( new TreeNode( "Node 2" ) );
    treeView1.SelectedNode = new TreeNode( "Node 1" );  
    
    // null reference exception here, we did not find a match
    MessageBox.Show( treeView1.SelectedNode.ToString( ) );
    

    So, you can instead find the node by value after clearing the control:

    TreeNode node1 = new TreeNode( "Node 1" );          
    TreeNode node2 = new TreeNode( "Node 2" );                          
    
    treeView1.Nodes.Add( node1 );
    treeView1.Nodes.Add( node2 );
    
    treeView1.Nodes.Clear( );
    
    treeView1.Nodes.Add( "Node 1" );
    treeView1.Nodes.Add( "Node 2" );
    
    // you can obviously use any value that you like to determine equality here
    var matches = from TreeNode x in treeView1.Nodes
                  where x.Text == node2.Text
                  select x;
    treeView1.SelectedNode = matches.First<TreeNode>( );
    
    // now correctly selects Node2
    MessageBox.Show( treeView1.SelectedNode.ToString( ) );
    

    Using LINQ here seems clunky, but the TreeNodeCollection class only exposes a Find() method which uses the node’s Name property. You could also use that, but equally clunky.

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