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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T22:05:53+00:00 2026-05-19T22:05:53+00:00

I’m using Google Guava r08 and JDK 1.6.0_23. I want to create an ImmutableSortedMap

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I’m using Google Guava r08 and JDK 1.6.0_23.

I want to create an ImmutableSortedMap using a builder. I know I can create the builder like this:

ImmutableSortedMap.Builder<Integer, String> b1 =
    new ImmutableSortedMap.Builder<Integer, String>(Ordering.natural());

and then use that to build maps, for example:

ImmutableSortedMap<Integer, String> map =
    b1.put(1, "one").put(2, "two").put(3, "three").build();

I noticed that class ImmutableSortedMap has a method naturalOrder() that returns a Builder with natural ordering. However, when I try to call this method, I get strange errors. For example, this gives a strange “; expected” error:

// Does not compile
ImmutableSortedMap.Builder<Integer, String> b2 =
    ImmutableSortedMap<Integer, String>.naturalOrder();

What is the correct syntax to call the naturalOrder() method?

The API documentation of the method mentions some compiler bug. Does that have anything to do with this method not working?

edit

MForster’s answer is good. But when leaving off the generics, I can’t do it “in one go”:

// Doesn't work, can't infer the types properly
ImmutableSortedMap<Integer, String> map =
    ImmutableSortedMap.naturalOrder().put(1, "one").put(2, "two").put(3, "three").build();

This does work:

ImmutableSortedMap<Integer, String> map =
    ImmutableSortedMap.<Integer, String>naturalOrder().put(1, "one").put(2, "two").put(3, "three").build();
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  1. Editorial Team
    Editorial Team
    2026-05-19T22:05:53+00:00Added an answer on May 19, 2026 at 10:05 pm

    The correct syntax is

    ImmutableSortedMap.Builder<Integer, String> b2 =
        ImmutableSortedMap.<Integer, String>naturalOrder();
    

    And you can drop the generics altogether, because they are inferred in this case:

    ImmutableSortedMap.Builder<Integer, String> b2 =
        ImmutableSortedMap.naturalOrder();
    
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