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Home/ Questions/Q 8519581
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T06:17:23+00:00 2026-06-11T06:17:23+00:00

I’m using gson to deserialize POJO objects from JSON representations. I’d like one of

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I’m using gson to deserialize POJO objects from JSON representations.

I’d like one of the fields in one of my POJOs to contain arbitrary JSON data. For example:

class B {
    public String stringField;
    public JsonObject jsonField;
}

I’d like to be able to call Gson.fromJson(json, B.class) on the following JSON:

{
    "stringField": "booger",
    "jsonField" :
    {
        "arbitraryField1": "foo"
    }
}

and have the resulting B.jsonField contain a JsonObject with an arbitraryField of value foo.

However, when I attempt to do this, jsonField is always an empty object ({}). In fact, more generally, it appears that the following always returns an empty object:

new Gson().fromJson("{ foo: 1 }", JsonObject.class)

I would expect the above to return an object containing a field named foo of value 1.

How can I have gson preserve arbitrary json data when deserializing json to POJOS?

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  1. Editorial Team
    Editorial Team
    2026-06-11T06:17:25+00:00Added an answer on June 11, 2026 at 6:17 am

    I was able to work around the problem by introducing a wrapper object that contains a JsonObject, and then writing a custom deserializer for that object that simply returns the original json. However, it seems like there must be a better way.

    For posterity, the deserializer and the trivial wrapper object look like the following:

    class MyJsonObjectWrapperDeserializer implements JsonDeserializer<MyJsonObjectWrapper> {
        @Override
        public MyJsonObjectWrapper deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
            return new MyJsonObjectWrapper(json.getAsJsonObject());
        }
    }
    
    class MyJsonObjectWrapper {
        public JsonObject json;
    
        public MyJsonObjectWrapper(JsonObject json) {
            this.json = json;
        }
    }
    
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