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Home/ Questions/Q 6987135
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:53:53+00:00 2026-05-27T18:53:53+00:00

I’m using HTTP encryption. if the encryption is false, webservice send a simple JSON

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I’m using HTTP encryption. if the encryption is false, webservice send a simple JSON with the value false and if the encryption is right, I send JSON array with datas.

test() is the method that “try” the api with a set of login:password.

I have trouble using the JSON that I receive (JSONException : End of input at character 0 )

Here’s the entiere code (I don’t think that this whole code will serve but…) and just after the code that make a JSON Exception :

private void test(String l, String p) {
        Log.v("MWW", "test de DialogBoxAuth");

        TextView erreur = (TextView) findViewById(R.id.erreurtext);
        String url = Main.app_preferences.getString("domain", "domain")+"api.php/1.0/authenticate";
        WebService webService = new WebService(url);
        Log.v("MWW", ".:" + url);

        // creation d'un MAP
        Map<String, String> params = new HashMap<String, String>();
        // Réponse JSON via le webservice avec les parametres

        response = webService.webGet("", params, l, p);

        HttpEntity entity = response.getEntity();

        Log.v("MWW", "entity = " + response.getEntity().toString());

        if (entity != null) {
            try {
                ret = EntityUtils.toString(response.getEntity());

                Log.v("MWW", "ret = " + ret.toString());

            } catch (IOException e) {
                Log.e("Groshie:", e.getMessage());
            }

            try {
                Log.v("MWW", "01");
                JSONArray childs = new JSONArray(ret);
                Log.v("MWW", "02");

                // affiche le JSON
                Log.v("MWW", "-->" + childs.toString());

                Log.v("MWW", "03");
                for (int j = 0; j < childs.length(); j++) {

                    JSONObject childNodeJSON = childs.getJSONObject(j);
                    // On récupère les données une par une et on les set dans la classe adéquate
                    String ok = "ok";
                    if (childNodeJSON.getString("status").equals(ok)) {
                        MajLoginPassword(l, p);
                        dismiss();
                        break;
                    } else {
                        erreur.setText("Login ou password incorrect");
                    }
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }else{
            erreur.setText("Vérifiez votre connexion à internet");
        }
    }

The code that provide the Exception :

if (entity != null) {
            try {
                ret = EntityUtils.toString(response.getEntity());

                Log.v("MWW", "ret = " + ret.toString());

            } catch (IOException e) {
                Log.e("Groshie:", e.getMessage());
            }

            try {
                Log.v("MWW", "01");
                JSONArray childs = new JSONArray(ret);
                Log.v("MWW", "02");

I can see the Logcat “01” but not the “02”, so “org.Json.JSONException : End of input at character 0” the error is coming from this line :

JSONArray childs = new JSONArray(ret);

Where and Why this Exception is leaved?

I can fix this problem alone… I dont understand it !
MANY thanks to read my problem, Clem’

Ok, many thanks ! After reading your comments, I’ve updated the code :

try {
                Log.v("MMW", "01 : ret = " + ret.toString());

                //JSONArray childs = new JSONArray(ret);
                JSONObject childs = new JSONObject(ret);

                Log.v("MMW", "02");

                // affiche le JSON
                Log.v("MMW", "-->" + childs.toString());

                Log.v("MMW", "03");
                for (int j = 0; j < childs.length(); j++) {


                    //JSONObject childNodeJSON = childs.getJSONObject(j);
                    JSONObject childNodeJSON = childs;

                    // On récupère les données une par une et on les set dans la classe adéquate
                    String ok = "ok";
                    if (childNodeJSON.getString("status").equals(ok)) {
                        MajLoginPassword(l, p);
                        dismiss();
                        break;
                    } else {
                        erreur.setText("Login ou password incorrect");
                    }
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }else{
            erreur.setText("Vérifiez votre connexion à internet");
        }

But there is a new exception:

JSONException : end of input at character 0 of ...

And the logcat says

ret = 
01 : ret =
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:53:54+00:00Added an answer on May 27, 2026 at 6:53 pm

    Have you tried changing

    JSONArray childs = new JSONArray(ret);
    

    to

    JSONObject childs = new JSONObject(ret);
    

    I had similar issues when trying to use a JSONArray initially. Since all JSON classes derive from JSONObject, this should work.

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