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Home/ Questions/Q 6942571
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:02:17+00:00 2026-05-27T13:02:17+00:00

I’m using javascript to parse through some strings. I have some strings that look

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I’m using javascript to parse through some strings.

I have some strings that look like this:

1234 1/2 Old Town Alexandria

I have written a regular expression to identify instances in which a fraction comes after the street number:

var addressFractionRegex = /^\d*\s+(1[/]\d)\s+/i;

What I would like to do is remove the fraction part of the regular expression from the source string only in cases where the entire regular expression is matched (ie: the fraction is preceded by a street number). In this case, I would end up with (removing the “1/2”):

1234 Old Town Alexandria

I would also like to save the part that I removed into another variable. So ideally, I’d end up with something like:

var street_address = '1234 Old Town Alexandria';
var fraction = '1/2';

How is this done in javascript?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:02:18+00:00Added an answer on May 27, 2026 at 1:02 pm

    replace can take a function:

    var fraction;
    var street_address = "1234 1/2 Old Town Alexandria".replace(/^\d*\s+(1[/]\d)\s+/i, function (match, capture) {
        fraction = capture.trim();
        return match.replace(capture,'')
    });
    
    fraction; // 1/2
    street_address; // 1234 Old Town Alexndria
    

    Demo

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