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Home/ Questions/Q 1047945
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T16:22:47+00:00 2026-05-16T16:22:47+00:00

I’m using javax.xml.transform.Transformer.transform() to convert one xml to another through an xsl stylesheet. I

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I’m using javax.xml.transform.Transformer.transform() to convert one xml to another through an xsl stylesheet. I would like to programatically set the sorting of the first level of children, but am unsure how to go about it. I’ve checked out the docs, but I don’t understand which type of property/parameter to use and how to specify in sort:

<xsl:sort select="*need to get property or parameter to here*"/>

I am open to other ideas, but would rather not parse the xml result into a w3c document.

Edit:
To clarify I am looking to set the sort key and direction for the elements in a xsl:for-each tag via the Transformer API.

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  1. Editorial Team
    Editorial Team
    2026-05-16T16:22:48+00:00Added an answer on May 16, 2026 at 4:22 pm

    This stylesheet:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:param name="pSortingBy" select="/root/@sorting"/>
        <xsl:template match="node()|@*">
            <xsl:copy>
                <xsl:apply-templates select="node()|@*"/>
            </xsl:copy>
        </xsl:template>
        <xsl:template match="/root">
            <xsl:copy>
                <xsl:apply-templates select="node()|@*">
                    <xsl:sort select="*[name()=$pSortingBy]"/>
                </xsl:apply-templates>
            </xsl:copy>
        </xsl:template>
    </xsl:stylesheet>
    

    With this input:

    <root sorting="prop4">
        <elem1>
            <prop1>A</prop1>
            <prop2>B</prop2>
            <prop3>C</prop3>
            <prop4>D</prop4>
            <prop5>A</prop5>
        </elem1>
        <elem2>
            <prop1>B</prop1>
            <prop2>C</prop2>
            <prop3>D</prop3>
            <prop4>A</prop4>
            <prop5>B</prop5>
        </elem2>
        <elem3>
            <prop1>C</prop1>
            <prop2>D</prop2>
            <prop3>A</prop3>
            <prop4>B</prop4>
            <prop5>C</prop5>
        </elem3>
    </root>
    

    Output:

    <root sorting="prop4">
        <elem2>
            <prop1>B</prop1>
            <prop2>C</prop2>
            <prop3>D</prop3>
            <prop4>A</prop4>
            <prop5>B</prop5>
        </elem2>
        <elem3>
            <prop1>C</prop1>
            <prop2>D</prop2>
            <prop3>A</prop3>
            <prop4>B</prop4>
            <prop5>C</prop5>
        </elem3>
        <elem1>
            <prop1>A</prop1>
            <prop2>B</prop2>
            <prop3>C</prop3>
            <prop4>D</prop4>
            <prop5>A</prop5>
        </elem1>
    </root>
    

    Note: You could define pSortingBy param to be any element name following specifications from your XSLT processor.

    Edit: I’m not a java expert, but I think you could do:

    javax.xml.transform.TransformerFactory transFact =
                           javax.xml.transform.TransformerFactory.newInstance( );
    javax.xml.transform.Transformer trans = transFact.newTransformer(xsltSource);
    trans.setParameter("pSortingBy", "prop5");
    
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