Question

I’m using jpa 2.0 and I have the following entity:

@Entity
public class Folder{

    @ElementCollection
    @CollectionTable(name="folder_files")
    private Set<String> files;      
    // .....
 }

Given a file name, I would like to delete all entries where files == theGivenFileName. In sql it would be something like this:

Delete from folder_files where files = XXX

Is there a way to perform this query using criteria-api?
If not, is there a way to perform this query using jpql?

UPDATE:
I think my question was not clear enough:
Since jpql uses entities (and not tables) I cannot just perform the sql written above plus since I’m using @ElementCollection I don’t know how to address this variablr or even deal with it. I would like to delete all entries in that collection (in my case, the files set) which holds a given value, from all entities. Is that possible using jpql or (even better) criteria-api?

Answer 1

You can use the like query just the syntax is slightly changed.

query = em.createQuery("SELECT i FROM Item i WHERE UPPER(i.name) LIKE :keyword ");
query.setParameter("keyword", "%" + keyword.toUpperCase() + "%");

You can read more on following link,

https://forums.oracle.com/forums/thread.jspa?threadID=423742

Updated:

@Noam you can do it: Like in Criteria API

List cats = sess.createCriteria(Cat.class)
    .add( Restrictions.like("name", "Fritz%") )
    .add( Restrictions.between("weight", minWeight, maxWeight) )
    .list();

Kindly read more on it at following link:

http://ctpconsulting.github.com/query/1.0.0.Alpha3/criteria.html

http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/querycriteria.html