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Home/ Questions/Q 8085873
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T18:16:11+00:00 2026-06-05T18:16:11+00:00

I’m using JQuery 1.7.2, trying to do a cross site Ajax request which should

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I’m using JQuery 1.7.2, trying to do a cross site Ajax request which should return a html page via 4 redirects.
Not my ideal world with all those redirects, but it’s part of the specification.

Now, using the following code:

$.ajax({
     type: "GET",
     url: myUrl,

     dataType: "script",
     success: function(data) {
      alert("success :"+ data);
     },
     error: function(jqXHR, textStatus, errorThrown) {
          alert("revoke: "+textStatus + ' / ' + errorThrown+"/"+jqXHR.status);
     },
     complete: function(jqXHR, textStatus){
         alert("complete : "+jqXHR.statusText + ": "+jqXHR.readyState);
     }
  });

I can see in Firebug/Safari Developer Tools, that all the redirects work (e.g. returns a 302 status with a Location header).
Then the strange thing happens: At the last page, which returns a 200 status, my script ends and I try to view the data coming back. But the output is just “Undefined”.
I agree on that I should not expect a script datatype when trying to get a html page, but when I tried with all the other datatypes (as defined in the jquery ajax page), the error handler is envoked and the status code is 0. All the while, in Safari DT, the status after the first redirect is just set as “(canceled)” (all the while the request just for the second redirect page just hangs in Firebug – but I’m just guessing that it has to do with their different implementation).

When I receive a 200 status, I can see in the debuggers that the last page has a size of some 18kb, which means that there should be some sort of data in it.

what to do?

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  1. Editorial Team
    Editorial Team
    2026-06-05T18:16:12+00:00Added an answer on June 5, 2026 at 6:16 pm

    You can’t redirect with AJAX, you can only send and get data to and from the server.

    For a redirection you have to use a “regular” HTTP request.

    It can also be done with javascript window.location = myUrl

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