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Home/ Questions/Q 8890275
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T22:27:52+00:00 2026-06-14T22:27:52+00:00

I’m using JQuery datepicker to allow user select a day and book something. then

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I’m using JQuery datepicker to allow user select a day and book something.
then I save the date in database,
later on I get the dates out of database and disable those days in datapicker so next user can’t select the booked days.
so far so good.

when a user select the day they want to book I need to disable the day after too.
I’m using php to save the chosen date in database together with some other information about user.
then i use ajax to load the dates thru php again and disable them.

how can i disable the they after? do I do it with php or javascript?
I have no idea how to get the day after selected date and how to save it? or should i save it or just add it later on when I get back the first date from ajax call and then loop thru the dates and get the day after with some function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T22:27:53+00:00Added an answer on June 14, 2026 at 10:27 pm

    I would use PHP if you can by simply returning a list of dates to the beforeShowDay method of your DatePicker.

    When you are adding a date from the database to the list, also use strtotime($Date, '1 day') to add the next day.

    Edit:

    $mysqli = new mysqli("localhost", "my_user", "my_password", "world");
    
    /* check connection */
    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }
    
    $query = "SELECT distinct Date, DATE_ADD(Date, INTERVAL 31 DAY) as Tomorrow from Table";
    $result = $mysqli->query($query);
    
    $Dates = array();
    
    /* numeric array */
    while(($row = $result->fetch_array(MYSQLI_NUM)) !== null)
    {
        //$Tomorrow = strtotime('1 day', $row['Date']);
        $Tomorrow = $row['Tomorrow'];
        if(!in_array($row['Date'], $Dates)) $Dates[] = $row['Date'];
        if(!in_array($Tomorrow, $Dates)) $Dates[] = $Tomorrow;
    }
    /* free result set */
    $result->free();
    
    /* close connection */
    $mysqli->close();
    
    header('content-type: application/json');
    die(json_encode(array('Dates' => $Dates)));
    
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