Question

I’m using JSON.NET Linq to JSON, when I execute the below I get the following argument exception:

Can not add Newtonsoft.Json.Linq.JValue to Newtonsoft.Json.Linq.JObject

What’s wrong with the code

string content = new JObject(
            new JObject("auth",
                        new JProperty("user", "[e-mail]"),
                        new JProperty("secret", "somepassword")
                ),
            new JObject("config",
                        new JProperty("template", "1")
                ),
            new JObject("data",
                        new JProperty("email", "body")
                )
            ).ToString();

Answer 1

As per the JSON.NET documentation, you need to wrap your JObjects in JProperties themselves:

string content = new JObject(
                   new JProperty("auth",
                     new JObject(
                       new JProperty("user", "[e-mail]"),
                       new JProperty("secret", "somepassword")
                     )
                   ),
                   new JProperty("config",
                     new JObject(
                       new JProperty("template", "1")
                     )
                   ),
                   new JProperty("data",
                     new JObject(
                       new JProperty("email", "body")
                     )
                   )
                 ).ToString();