Question

I’m using Jython from within Java; so I have a Java setup similar to below:

String scriptname="com/blah/myscript.py"
PythonInterpreter interpreter = new PythonInterpreter(null, new PySystemState());
InputStream is = this.getClass().getClassLoader().getResourceAsStream(scriptname);
interpreter.execfile(is);

And this will (for instance) run the script below:

# myscript.py:
import sys

if __name__=="__main__":
    print "hello"
    print sys.argv

How I pass in ‘commandline’ arguments using this method ?
(I want to be able to write my Jython scripts so that I can also run them on the commandline with ‘python script arg1 arg2’).

Answer 1

I’m using Jython 2.5.2 and runScript didn’t exist, so I had to replace it with execfile. Aside from that difference, I also needed to set argv in the state object before creating the PythonInterpreter object:

String scriptname = "myscript.py";

PySystemState state = new PySystemState();
state.argv.append (new PyString ("arg1"));
state.argv.append (new PyString ("arg2"));

PythonInterpreter interpreter = new PythonInterpreter(null, state);
InputStream is = Tester.class.getClassLoader().getResourceAsStream(scriptname);
interpreter.execfile (is);

The argv list in the state object initially has a length of 1, with an empty string in it, so the preceding code results in the output:

hello
['', 'arg1', 'arg2']

If you need argv[0] to be the actual script name, you’d need to create the state like this:

PySystemState state = new PySystemState();
state.argv.clear ();
state.argv.append (new PyString (scriptname));      
state.argv.append (new PyString ("arg1"));
state.argv.append (new PyString ("arg2"));

Then the output is:

hello
['myscript.py', 'arg1', 'arg2']