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Home/ Questions/Q 8683737
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:07:26+00:00 2026-06-12T22:07:26+00:00

I’m using lighttpd 1.4.28 Here is my redirect rule : $HTTP[host] =~ ^([^.]+\.[^.]+)$ {

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I’m using lighttpd 1.4.28

Here is my redirect rule :

$HTTP["host"] =~ "^([^.]+\.[^.]+)$" {
        url.redirect = ( "^/(.*)" => "http://www.%0/$1" )
}

It’s supposed to redirect anydomain.anytld to http://www.anydomain.anytld and it works like a charm like I’ve written it here (of course, using %1 also works, since it refers to the parentheses.)

Yet, I’m baffled as to why it only works with the pair of parentheses you can see in the trigger regex.

%0 is supposed to catch the whole result, isn’t it ? It doesn’t even refer to a pair of parenthese, unlike %1, %2, etc. But if I remove those parentheses, like this :

$HTTP["host"] =~ "^[^.]+\.[^.]+$" {
        url.redirect = ( "^/(.*)" => "http://www.%0/$1" )
}

I get this error when trying to restart lighttpd :

unreachable else condition 2012-10-17 11:34:10: (configfile.c.918)
source: /etc/lighttpd/lighttpd.conf line: 173 pos: 14 parser failed
somehow near here: (EOL)

Thanks !

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:07:26+00:00Added an answer on June 12, 2026 at 10:07 pm

    It’s because %0 matches the entire substring or the first expression, which, by definition is the enclosing () set. This would allow you to use a more complicated regex with nested (ie ((()))) parenthesis, and pulling the entirety of it. From what I can understand, that is the construct of Lighttpd’s regex parser.

    http://redmine.lighttpd.net/projects/1/wiki/Docs_ModRewrite

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