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Home/ Questions/Q 815741
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:43:54+00:00 2026-05-15T01:43:54+00:00

I’m using Linq To Nhibernate, and with a HQL statement I can do something

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I’m using Linq To Nhibernate, and with a HQL statement I can do something like this:

string hql = "from Entity e order by rand()";

Andi t will be ordered so random, and I’d link to know How can I do the same statement with Linq to Nhibernate ?

I try this:

var result = from e in Session.Linq<Entity> 
             orderby new Random().Next(0,100) 
             select e;

but it throws a exception and doesn’t work…

is there any other way or solution?

Thanks

Cheers

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T01:43:54+00:00Added an answer on May 15, 2026 at 1:43 am

    I guess Linq to NHibernate is unable to convert the Random.Next call to SQL…

    An option would be to sort the results after you retrieve them from the DB :

    var rand = new Random();
    var query =  from e in Session.Linq<Entity> 
                 select e;
    var result = from e in query.AsEnumerable()
                 orderby rand.Next(0,100) 
                 select e;
    

    Note that you need to use a single instance of Random, because the seed is based on the current number of ticks ; if you create several instances of Random with very short interval, they will have the same seed, and generate the same sequence.

    Anyway, sorting a collection based on a random number is not such a good idea, because the sort won’t be stable and could theoretically last forever. If you need to shuffle the results, you can use the Fisher-Yates algorithm :

    var result = Session.Linq<Entity>().ToArray();
    var rand = new Random();
    for(int i = result.Length - 1; i > 0; i--)
    {
        int swapIndex = rand.Next(i + 1);
        var tmp = result[i];
        result[i] = result[swapIndex];
        result[swapIndex] = tmp;
    }
    
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