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Home/ Questions/Q 7707187
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T00:17:48+00:00 2026-06-01T00:17:48+00:00

I’m using matplotlib to plot some data as 2D curves in a 3D axes.

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I’m using matplotlib to plot some data as 2D curves in a 3D axes. I use the ax = axes3d.Axes3D() to define my axes and ax.plot(x, y, zs='z') to plot my 2D curves in the 3D space.

Now I want to add something that looks like what is on this page http://matplotlib.sourceforge.net/examples/mplot3d/polys3d_demo.html, but I want to enter directly the coordinates of the vertex. In this example they have a fixed z array and they plot polygons with vertices (x,y), whereas what I want is z(x) and (x,y) vertices. Does anyone know how to do something like this?

And actually I don’t need the collection thing, I just want to plot one big square in an arbitrary direction.

I tried to simply enter the coordinates and use ax.plot():

verts = np.array([[0,0,0], [0,1,0], [1,1,1], [1,0,1], [0,0,0]])
ax.plot(verts[:,0], verts[:,1], verts[:,2], zdir='y')

and it indeed plots a square, but I can’t (or don’t know how to) fill the face.

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  1. Editorial Team
    Editorial Team
    2026-06-01T00:17:49+00:00Added an answer on June 1, 2026 at 12:17 am

    I hope this is what you wanted!
    this

    My rectangle will go from 0 to 10. So MAX=10.
    What I did at first is try to define an axis between z and x.
    z=MAX-x was my choice.

    And then I preceded to draw this axis for every small increment of x, thus creating the rectangle.
    This is the code:

    anArray = []    
    for i in range(0, 101, 1):
        z = float(i)/10        
        #print "x: ", x
        y = 10 - z
        #print "y: ", y      
        for a in range(0, 101, 1):          
            anArray.append([float(a)/10, y, z])
        #endfor                    
    #endfor
    verts = np.array(anArray)
    ax.plot(verts[:,0],verts[:,1],verts[:,2], zdir='y')
    
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