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Home/ Questions/Q 575337
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:55:46+00:00 2026-05-13T13:55:46+00:00

I’m using Mercurial and I’ve got into a terrible mess locally, with three heads.

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I’m using Mercurial and I’ve got into a terrible mess locally, with three heads. I can’t push, and I just want to delete all my local changes and commits and start again with totally clean code and a clean history.

In other words, I want to end up with (a) exactly the same code locally as exists in the tip of the remote branch and (b) no history of any local commits.

I know hg update -C overwrites any local changes. But how do I delete any local commits?

To be clear, I have no interest in preserving any of the work I’ve done locally. I just want the simplest way to revert back to a totally clean local checkout.

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:55:47+00:00Added an answer on May 13, 2026 at 1:55 pm

    When the simplest way (a new hg clone) isn’t practical, I use hg strip:

    % hg outgoing -l 1
    % hg strip $rev # replace $rev with the revision number from outgoing
    

    Repeat until hg outgoing stays quiet. Note that hg strip $rev obliterates $rev and all its descendants.

    Note that you may have to first enable strip in your Mercurial settings.

    PS: an even smarter approach is to use the revset language, and do:

    % hg strip 'roots(outgoing())'
    
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