Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8693363
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T00:31:49+00:00 2026-06-13T00:31:49+00:00

I’m using microsoft Access. If this query: (SELECT FERMENT.FermentId FROM FERMENT INNER JOIN [BELGIUM

  • 0

I’m using microsoft Access.

If this query:

(SELECT FERMENT.FermentId
FROM FERMENT
INNER JOIN [BELGIUM BEER]
ON
FERMENT.FermentName = [BELGIUM BEER].FermentId ORDER BY [BELGIUM BEER].BeerId) a

returns FermentId, how do I update a different table with that column?

Example:

UPDATE EXAMPLETABLE
SET EXAMPLETABLE.FermentId = a.FermentId
FROM a
(SELECT FERMENT.FermentId
FROM FERMENT
INNER JOIN [BELGIUM BEER]
ON
FERMENT.FermentName = [BELGIUM BEER].FermentId ORDER BY [BELGIUM BEER].BeerId) a
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T00:31:50+00:00Added an answer on June 13, 2026 at 12:31 am

    Assuming that the sub-query returns more than one value, you need a second key to connect (JOIN) between the new values and the table you want to update (EXAMPLETABLE).

    In this case I would try something like this:

    UPDATE T 
    SET    T.FERMENTID = A.FERMENTID 
    FROM   EXAMPLETABLE AS T 
           INNER JOIN (SELECT FERMENT.FERMENTID, 
                              FERMENT.OTHERID 
                       FROM   FERMENT 
                              INNER JOIN [BELGIUM BEER] 
                                      ON FERMENT.FERMENTNAME = 
                                         [BELGIUM BEER].FERMENTID 
                       ORDER  BY [BELGIUM BEER].BEERID) AS A 
                   ON A.OTHERID = T.OTHERID 
    

    If this isn’t the case and the sub-query returns a single value, try something like this:

    UPDATE EXAMPLETABLE 
    SET    T.FERMENTID = (SELECT FERMENT.FERMENTID
                          FROM   FERMENT 
                                 INNER JOIN [BELGIUM BEER] 
                                         ON FERMENT.FERMENTNAME = 
                                            [BELGIUM BEER].FERMENTID 
                          ORDER  BY [BELGIUM BEER].BEERID)
    

    Note that in this case you need to guarantee that the sub-query will never return more than one row!

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

For some reason, after submitting a string like this Jack’s Spindle from a text
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
Does anyone know how can I replace this 2 symbol below from the string
I'm new to using the Perl treebuilder module for HTML parsing and can't figure
That's pretty much it. I'm using Nokogiri to scrape a web page what has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I am reading a book about Javascript and jQuery and using one of the
this is what i have right now Drawing an RSS feed into the php,
I'm using v2.0 of ClassTextile.php, with the following call: $testimonial_text = $textile->TextileRestricted($_POST['testimonial']); ... and

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.