Question

I’m using Oracle 10g.

Question: How can I write query to return just ID only if ALL the codes for that ID end in 6?

I don’t want ID=1 because not all its codes end in 6.

TABLE_A

ID  Code
===============
1   100  
1   106
2   206
3   316
3   326
4   444

Desired Result:
ID
==
2
3

Answer 1

You simply want each ID where the count of rows for that id is the same as the count of rows where the third digit is six.

SELECT ID
FROM TABLE_A
GROUP BY ID
HAVING COUNT(*) = COUNT(CASE WHEN SUBSTR(code,3,1) = '6' THEN 1 END)