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Home/ Questions/Q 8845357
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:43:14+00:00 2026-06-14T11:43:14+00:00

I’m using PostgreSQL 8.1, and I have two databases with one table names clients

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I’m using PostgreSQL 8.1, and I have two databases with one table names clients that are identical and contain +-50k rows each.

I need to obtain all ids in one table that aren’t in the other, I have the following solution

$sql = "SELECT id FROM clients WHERE id NOT IN(".pg_query($conn1,'SELECT id FROM clients').")";
$result = pg_query($conn2,$sql);

Before I run this, is this a good way to do it via PHP or are the other better faster ways?

Unfortunately I cant use dblink since I do not have privileges to install it.

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:43:15+00:00Added an answer on June 14, 2026 at 11:43 am

    If you can’t use a database link I think you will have to do it in the middleware – and this middleware should have a lot of RAM.

    I would also recommend not to use PHP for this purpose, but if you have no other possibility, I would do it like this:

    $ids = array();
    $idsNotExist = array();
    $resultDb1 = pg_query('SELECT id FROM db1');
    while ( $row = pg_fetch_dontknowtheexactfunction_row($resultDb1) ) {
      array_push($ids, $row['id']);
    }
    
    $resultDb2 = pg_query('SELECT id FROM db2');
    while ( $row = pg_fetch($resultDb2) ) {
      if ( !in_array($ids, $row['id']) ) {
        array_push($idsNotExist, $row['id']);
      }
    }
    

    Best way would of course be, because ID is primary key, to write an own in_array-function which removes the ID from haystack when it’s found because it will not be searched for again and the next search loop will be a bit faster.

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