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Home/ Questions/Q 3286782
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T20:25:09+00:00 2026-05-17T20:25:09+00:00

I’m using private inheritance in the implementation of two very related classes. The using

  • 0

I’m using private inheritance in the implementation of two very related classes. The using Base::X; is very useful and elegant. However, I can’t seem to find an elegant solution for reusing the base class’s swap function.

class A
{
public:
   iterator       begin();
   const_iterator begin() const;
   const_iterator cbegin() const;

   A clone();

   void swap( A& other );
};

class Const_A : private A
{
public:
   // I think using A::A; will be valid in C++0x
   Const_A( const A& copy) : A(copy) { }

   // very elegant, concise, meaningful
   using A::cbegin;

   // I'd love to write using A::begin;, but I only want the const overload
   // this is just forwarding to the const overload, still elegant
   const_iterator begin() const
   { return A::begin(); }

   // A little more work than just forwarding the function but still uber simple
   Const_A clone()
   { return Const_A(A::clone()); }

   // What should I do here?
   void swap( Const_A& other )
   { /* ??? */ }
};

So far the only thing I can come up with is copy-pasting A::swap‘s definition into Const_A::swap‘s definition, YUCK!

Is there an elegant solution to to reuse the private base class’s swap?

Is there a cleaner way to implement what I’m trying to do here (a const wrapper for a class)?

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  1. Editorial Team
    Editorial Team
    2026-05-17T20:25:09+00:00Added an answer on May 17, 2026 at 8:25 pm

    Well, can’t you just call the base’s version of swap?

    void swap( Const_A& other )
    {
        A::swap(other); // swaps the `A` portion of `this`.
        // …
    }
    

    In place of …, you’d normally swap the members pertaining only to Const_A, not A but since there aren’t any in your particular case, this is all that you should need.

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