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Home/ Questions/Q 6579543
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:54:42+00:00 2026-05-25T15:54:42+00:00

I’m using pymongo and currently have a single collection. The collection holds documents representing

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I’m using pymongo and currently have a single collection. The collection holds documents representing matches in a football league. Each match has goals. Currently the goals are implemented as a list contained in the match object:

{'matchID':1000,
  'goals':[{'goalID':200,'scorer':'A'},
           {'goalID':201,'scorer':'B']}
          ]
}
{'matchID':1001,
  'goals':[{'goalID':211,'scorer':'C'},
           {'goalID':212,'scorer':'D']}
          ]
}

What I want to do is query for all goals with an ID higher than, say 201. What I would expect from the data above is that I would get goals 211 and 212.

How do I implement this in mongodb – I’m trying things like:

x = mycollection.find({'$gt':[{'match.goals.goalID':201}]})

but that isn’t getting me anywhere. Should I be splitting goals into a separate collection and manually referencing instead? Once a goal is entered, it is never touched again – it will be read only.

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:54:43+00:00Added an answer on May 25, 2026 at 3:54 pm

    You’ve got a couple of issues with that query:

    1. The correct dotted field name for the goalID elements of the objects nested in the arrays should be “goals.goalID” — that is, remove the preceding “match.“
    2. The correct order for $gt (and friends: $gte, $lt, $lte) is field: {$operator: value}, like:

      db.mycollection.find({"goals.goalID": {"$gt": 201}})

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