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Home/ Questions/Q 8506799
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T02:41:28+00:00 2026-06-11T02:41:28+00:00

I’m using Python 2.7 in Google App Engine and can’t seem to get my

  • 0

I’m using Python 2.7 in Google App Engine and can’t seem to get my app.yaml file set up right.

My goal is so that if I go to http://localhost/carlos/ I get an executed carlos.py

Here is my directory structure:

app\
   \app.yaml
   \main.py
   \carlos.py

Here is my current app.yaml file:

application: myapp
version: 1
runtime: python27
api_version: 1
threadsafe: yes

handlers:
- url: /carlos/.*
  script: carlos.app

- url: .*
  script: main.app

and my carlos.py file is:

import webapp2

class MainHandler(webapp2.RequestHandler):
  def get(self):
    self.response.out.write("Hello, Carlos!")

app = webapp2.WSGIApplication([('/carlos', MainHandler)],
                              debug=True)

However all I’m getting now is a 404 Not Found error. Any thoughts?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T02:41:29+00:00Added an answer on June 11, 2026 at 2:41 am

    I was able to determine the solution and figured I’d post it for anyone out there.

    In my carlos.py file I needed to replace:

    app = webapp2.WSGIApplication([('/', MainHandler)],
                                  debug=True)
    

    with

    app = webapp2.WSGIApplication([('/carlos/', MainHandler)],
                                  debug=True)
    

    It appears that the first argument for the WSGIApplication is referring to the TOTAL path from your root web address as opposed to the INCREMENTAL path from which it was originally directed.

    I’m selecting this answer over what was provided by Littm because I’d like to keep using WSGI

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