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Home/ Questions/Q 6740689
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T11:38:08+00:00 2026-05-26T11:38:08+00:00

I’m using Python 3 to download a file: local_file = open(file_name, w + file_mode)

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I’m using Python 3 to download a file:

local_file = open(file_name, "w" + file_mode)
local_file.write(f.read())
local_file.close()

This code works, but it copies the whole file into memory first. This is a problem with very big files because my program becomes memory hungry. (Going from 17M memory to 240M memory for a 200 MB file)

I would like to know if there is a way in Python to download a small part of a file (packet), write it to file, erase it from memory, and keep repeating the process until the file is completely downloaded.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T11:38:09+00:00Added an answer on May 26, 2026 at 11:38 am

    Try using the method described here:

    Lazy Method for Reading Big File in Python?

    I am specifically referring to the accepted answer. Let me also copy it here to ensure complete clarity of response.

        def read_in_chunks(file_object, chunk_size=1024):
            """Lazy function (generator) to read a file piece by piece.
            Default chunk size: 1k."""
            while True:
                data = file_object.read(chunk_size)
                if not data:
                    break
                yield data
    
    
        f = open('really_big_file.dat')
        for piece in read_in_chunks(f):
            process_data(piece)
    

    This will likely be adaptable to your needs: it reads the file in smaller chunks, allowing for processing without filling your entire memory. Come back if you have any further questions.

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