Question

I’m using python markdown 2.1.1. When I try to markdown a list, why is there a carriage return before

in the list? e.g.,

text = u" - this is a paragraph\r\n\r\n - this is a line\r\n"
markdown.markdown(text)
# produces: u'<ul>\n<li>\n<p>this is a paragraph</p>\n</li>\n<li>\n<p>this is a line</p>\n</li>\n</ul>'

According to the Markdown Syntax, the expected output should be

u'<ul>\n<li><p>this is a paragraph</p></li>\n<li>\n<p>this is a line</p>\n</li>\n</ul>'

No \n before and after the <p> element, right?
This makes the page really ugly because I’m styling the block using white-space: pre-line, so the output would look like

- 
   this is a paragraph

-  this is a line

Answer 1

Markdown does not obey the syntax completely. Use markdown2, which normally behaves better.

>>> import markdown2
>>> print markdown2.markdown(u" - this is a paragraph\r\n\r\n - this is a line\r\n")
<ul>
<li><p>this is a paragraph</p></li>
<li><p>this is a line</p></li>
</ul>

# using fenced-code-blocks
>>> print markdown2.markdown('\n\n```python\nprint('Hello')\n```', extras=['fenced-code-blocks'])
<div class="codehilite"><pre><code><span class="k">print</span><span class="p">(</span><span class="s">&quot;Hello&quot;</span><span class="p">)</span>
</code></pre></div>

Note, you need to write two '\n' before the first ``` to enable the regexp matching of fenced-code-blocks.