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Home/ Questions/Q 7992137
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:28:59+00:00 2026-06-04T13:28:59+00:00

I’m using replaceAll() in Groovy and getting caught out when the replacement string contains

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I’m using replaceAll() in Groovy and getting caught out when the replacement string contains the $ symbol (which is interpreted as a regexp group reference).

I’m finding I have to do a rather ugly double replacement:

def regexpSafeReplacement = replacement.replaceAll(/\$/, '\\\\\\$')
replaced = ("foo" =~ /foo/).replaceAll(regexpSafeReplacement)

Where:

replacement = "$bar"

And desired result is:

replaced = "$bar"

Is there a better way of performing this replacement without the intermediate step?

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:29:00+00:00Added an answer on June 4, 2026 at 1:29 pm

    As it says in the docs for replaceAll, you can use Matcher.quoteReplacement

    def input = "You must pay %price%"
    
    def price = '$41.98'
    
    input.replaceAll '%price%', java.util.regex.Matcher.quoteReplacement( price )
    

    Also note that instead of double quotes in:

    replacement = "$bar"
    

    You want to use single quotes like:

    replacement = '$bar'
    

    As otherwise Groovy will treat it as a template and fail when it can’t find the property bar

    So, for your example:

    import java.util.regex.Matcher
    assert '$bar' == 'foo'.replaceAll( 'foo', Matcher.quoteReplacement( '$bar' ) )
    
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