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Home/ Questions/Q 8152873
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T15:50:15+00:00 2026-06-06T15:50:15+00:00

I’m using Requests to scrape a website. The content of the html gets successfully

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I’m using Requests to scrape a website. The content of the html gets successfully saved in the variable r but in the if-statement I get the said error

[...]
for line in r:  
    link = re.findall(r ("""onclick="window.location.href='([^'])'""",line)
    if link: 
        print ('something')
        cmd = ('some commands to get info page') 
        call(cmd,shell=True)

        download = re.sub(something)
        cmd = ('some commands to download the file') 
        call(cmd,shell=True)
r.close()

I looked it up in the documentation and the syntax appears to be correct. I then suspected the error to be in the line before. Here I search for the line with the phrase onclick=”window.location.href=’ and want the link that follows it to be processed (in the code afterwards). The () encapsuled part should be what is returned, right?

Does anybody see an error? in

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  1. Editorial Team
    Editorial Team
    2026-06-06T15:50:16+00:00Added an answer on June 6, 2026 at 3:50 pm

    Perhaps the brackets?

    #                1  2                                                 2                   
    link = re.findall(r ("""onclick="window.location.href='([^'])'""",line)
    

    It looks like you forgot to close the bracket for findall.

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