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Home/ Questions/Q 8976611
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:11:15+00:00 2026-06-15T19:11:15+00:00

I’m using Ruby and I’m communicating with a network endpoint that requires the formatting

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I’m using Ruby and I’m communicating with a network endpoint that requires the formatting of a ‘header’ prior to sending the message itself.

The first field in the header must be the message length which is defined as a 2 binary byte message length in network byte order.

For example, my message is 1024 in length. How do I represent 1024 as binary two-bytes?

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:11:16+00:00Added an answer on June 15, 2026 at 7:11 pm

    The standard tools for byte wrangling in Ruby (and Perl and Python and …) are pack and unpack. Ruby’s pack is in Array. You have a length that should be two bytes long and in network byte order, that sounds like a job for the n format specifier:

    n | Integer | 16-bit unsigned, network (big-endian) byte order

    So if the length is in length, you’d get your two bytes thusly:

    two_bytes = [ length ].pack('n')
    

    If you need to do the opposite, have a look at String#unpack:

    length = two_bytes.unpack('n').first
    
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