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Home/ Questions/Q 6838051
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:33:01+00:00 2026-05-26T23:33:01+00:00

I’m using scatter3d and the 3 axes just have two endpoint values. how can

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I’m using scatter3d and the 3 axes just have two endpoint values. how can I get labels throughout the entire axis, just like the normal plot() function does?

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:33:01+00:00Added an answer on May 26, 2026 at 11:33 pm

    Oh well. I took it as a challenge.

    Obviously you need to:

    require(rgl)
    require(car)
    require(mgcv) # for the example
    

    Copy the car:::scatter3d.default code and paste it back, assigning it to scatter3d.default.

    Add these lines early in the code for scatter3d.default:

     showLabels3d <- car:::showLabels3d  
     nice <- car:::nice  
      # since you will be losing their connection to the unexposed fns in car
    

    Then in the code block following the second if(axis.scales){ ...}, substitute this code:

     if (axis.scales) {
       x.labels <-  seq(lab.min.x, lab.max.x, 
                           by=diff(range(lab.min.x, lab.max.x))/4)
       x.at <- seq(min.x, max.x, by=nice(diff(range(min.x, max.x))/4))
          rgl.texts(x.at, -0.05, 0, x.labels, col = axis.col[1])
    
       z.labels <-  seq(lab.min.z, lab.max.z, 
                           by=diff(range(lab.min.z, lab.max.z))/4)
       z.at <- seq(min.z, max.z, by=diff(range(min.z, max.z))/4)
          rgl.texts(0, -0.1, z.at, z.labels, col = axis.col[3])
    
       y.labels <-  seq(lab.min.y, lab.max.y, 
                           by=diff(range(lab.min.y, lab.max.y))/4)
       y.at <- seq(min.y, max.y, by=diff(range(min.y, max.y))/4)
          rgl.texts(-0.05, y.at, -0.05, y.labels, col = axis.col[2])
                    }
    

    (You may need to replace the code for scatter3d.formula so that doesn’t look in the car NAMESPACE for the routinely dispatched scatter method. I simply replaced the scatter3d call inside car:::scatter3d.formula with “scatter3d.default” so the interpreter would first look at the newly defined function.)

    Edit: a better method than mucking with scatter3d.formula is to assign the car namespace/environment to the new function with this code:

    environment(scatter3d.default) <- environment(car:::scatter3d.formula)
    

    Then if you do this:

    scatter3d(prestige ~ income + education, data=Duncan)
    

    You get this (taken with a screenshot program)
    enter image description here

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