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Home/ Questions/Q 6631989
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:37:25+00:00 2026-05-25T22:37:25+00:00

I’m using SQLAlchemy declarative base to define my model. I defined a property name

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I’m using SQLAlchemy declarative base to define my model. I defined a property name that is computed from one the columns (title):

class Entry(Base):
    __tablename__ = "blog_entry"
    id = Column(Integer, primary_key=True)
    title = Column(Unicode(255))
    ...

    @property
    def name(self):
        return re.sub(r'[^a-zA-Z0-9 ]','',self.title).replace(' ','-').lower()

When trying to perform a query using name, SQLAlchemy throws an error:

Session.query(Entry).filter(Entry.name == my_name).first()
>>> ArgumentError: filter() argument must be of type sqlalchemy.sql.ClauseElement or string

After investigating for a while, I found that maybe comparable_using() could help, but I couldn’t find any example that shows a comparator that references another column of the table.

Is this even possible or is there a better approach?

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:37:26+00:00Added an answer on May 25, 2026 at 10:37 pm

    From SqlAlchemy 0.7 you can achieve this using hybrid_property
    see the docs here: http://www.sqlalchemy.org/docs/orm/extensions/hybrid.html

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