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Home/ Questions/Q 9282011
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T18:15:57+00:00 2026-06-18T18:15:57+00:00

I’m using SQLAlchemy with a MySQL database and I’d like to count the rows

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I’m using SQLAlchemy with a MySQL database and I’d like to count the rows in a table (roughly 300k). The SQLAlchemy count function takes about 50 times as long to run as writing the same query directly in MySQL. Am I doing something wrong?

# this takes over 3 seconds to return
session.query(Segment).count()

However:

SELECT COUNT(*) FROM segments;
+----------+
| COUNT(*) |
+----------+
|   281992 |
+----------+
1 row in set (0.07 sec)

The difference in speed increases with the size of the table (it is barely noticeable under 100k rows).

Update

Using session.query(Segment.id).count() instead of session.query(Segment).count() seems to do the trick and get it up to speed. I’m still puzzled why the initial query is slower though.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T18:15:59+00:00Added an answer on June 18, 2026 at 6:15 pm

    Unfortunately MySQL has terrible, terrible support of subqueries and this is affecting us in a very negative way. The SQLAlchemy docs point out that the “optimized” query can be achieved using query(func.count(Segment.id)):

    Return a count of rows this Query would return.

    This generates the SQL for this Query as follows:

    SELECT count(1) AS count_1 FROM (
         SELECT <rest of query follows...> ) AS anon_1
    

    For fine grained control over specific columns to count, to skip the
    usage of a subquery or otherwise control of the FROM clause, or to use
    other aggregate functions, use func expressions in conjunction with
    query(), i.e.:

    from sqlalchemy import func
    
    # count User records, without
    # using a subquery.
    session.query(func.count(User.id))
    
    # return count of user "id" grouped
    # by "name"
    session.query(func.count(User.id)).\
            group_by(User.name)
    
    from sqlalchemy import distinct
    
    # count distinct "name" values
    session.query(func.count(distinct(User.name)))
    
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