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Home/ Questions/Q 9184569
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T19:05:11+00:00 2026-06-17T19:05:11+00:00

I’m using the example here to add menus to my website. In the original

  • 0

I’m using the example here to add menus to my website. In the original HTML there is a div with this menu inside of it. I invoke the circleMenu effect on it.

            <ul id="container" >
            <li class="ui-state-default">example1
                <!--menu button-->
                <ul class="menu" id="menu6">
                    <li><a href="#"></a></li>
                    <li><a href="#" alt="Edit" title="Edit"><img src="images/edit.jpg" /></a></li>
                    <li><a href="#" alt="Copy" title="Copy"><img src="images/copy.jpg" /></a></li>
                    <li><a href="#" alt="Delete" title="Delete"><img src="images/delete.jpg" /></a></li>
                </ul>
            </li>
        </ul>

                $('.menu').circleMenu({
                direction: 'right',
                circle_radius: 80,
                item_diameter: 20,
                trigger: 'click'
            });

Now, at some other place in the page, I create the example2 list item, and the same menu. Except this time, the circleMenu effect will not be attached to it, because it was just created. How do I apply the effect immediately after creation? or modify the existing call to use all current ‘.menu’ items as of that moment?

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  1. Editorial Team
    Editorial Team
    2026-06-17T19:05:13+00:00Added an answer on June 17, 2026 at 7:05 pm

    Use jquery .on()

    $('.menu').on("load", data, function(event){
        $('.menu').circleMenu({
             direction: 'right',
             circle_radius: 80,
             item_diameter: 20,
             trigger: 'click'
        });
    });
    

    You can pass data in the second argument, or simply set it to null.

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