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Home/ Questions/Q 9169861
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:56:13+00:00 2026-06-17T15:56:13+00:00

I’m using the GCC C Compiler as my compiler and I have a program

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I’m using the “GCC C Compiler” as my compiler and I have a program that takes in inputs as stdin using “fgets” and then I’m using multiple printf’s to print results due to certain inputs.

However, my problem is I want the output to occur between the fgets, which they do reside in my code, however currently nothing prints until I return from main and the program ends.

Input Code:

int get_inputs(char** operands, char* delim) {
  if (fgets(input,sizeof(input),stdin) == NULL) return 0;  /* End of file */

  /* Parse with StringParse, returns number of substrings */
  return StringParse(input, operands, delim, 2, "+-*/^ ");
}

Output Code: (In a While(1) loop)

count = get_inputs(operands, delim);

switch(count) {
case 0:
    printf("User Terminated\n");
    return 0;  /* User Terminated */

case 1: /* Single Value Input */
    accumulator = atof(operands[0]);
    printf("%g\n", accumulator);
    break;

case 2:
    if(strlen(operands[0]) == 0) { /* Operation First use Accumulator as input */
        accumulator = doMath(accumulator, atof(operands[1]), delim[0]);
        printf("%g\n", accumulator);
    }
    else { /* Two new values, replace Accumulator */
        accumulator = doMath(atof(operands[0]), atof(operands[1]), delim[0]);
        printf("%g\n", accumulator);
    }
    break;

default:
    printf("Invalid Input\n"); /* Invalid Input or Error */
    break;
}

Every other function is just doing math or string parsing.

Thanks in Advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T15:56:14+00:00Added an answer on June 17, 2026 at 3:56 pm

    This is because stdout is buffered to improve performance. The data is only pushed to the output pipe in larger chunks. To force this to happen at a certain point, add

    fflush(stdout);
    

    In the code which is writing to stdout.

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