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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:00:10+00:00 2026-05-27T12:00:10+00:00

I’m using the Muenchian method to group nodes in an XML document. As part

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I’m using the Muenchian method to group nodes in an XML document.

As part of my output, I’d like to select all of the nodes to which I have not assigned a key.

I’ve tried

<xsl:apply-templates select="*[key('kcWWPN','')]"/>

but that doesn’t appear to be working correctly, in that it is selecting no nodes.

Any suggestions on the right way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:00:11+00:00Added an answer on May 27, 2026 at 12:00 pm

    As part of my output, I’d like to select all of the nodes to which I
    have not assigned a key.

    Good question, +1.

    Here are two different, but simple solutions:

    For simplicity I will assume that we are keying only elements, but the two solutions below can naturally be extended to cover other types of nodes.

    I. Simply, define a counter-key:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>
    
     <xsl:key name="kDByClass" match="d" use="@class"/>
    
     <xsl:key name="kCounterKey" match="*[not(self::d)]" use="."/>
    
     <xsl:template match="*[key('kCounterKey', .)]">
      Counter Keyed: <xsl:value-of select="name()"/>
    
      <xsl:apply-templates/>
     </xsl:template>
    
     <xsl:template match="text()"/>
    </xsl:stylesheet>
    

    when this transformation is applied on the following XML document (borrowed from @lwburk):

    <root>
        <d class="test">1</d>
        <d class="test">2</d>
        <d class="something">1</d>
        <q>3</q>
    </root>
    

    the wanted, correct result is produced:

      Counter Keyed: root
      Counter Keyed: q
    

    II. Use the set difference of all elements and all keyed elements (the latter is found using Muenchian grouping):

    This solution is simpler than the first, because one doesn’t need to compose a counter-key:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>
    
     <xsl:key name="kDByClass" match="d" use="@class"/>
    
     <xsl:key name="kCounterKey" match="*[not(self::d)]" use="."/>
    
     <xsl:variable name="vKeyedValues" select=
     "//*[generate-id()
         = generate-id(key('kDByClass', @class)[1])
         ]
          /@class
      "/>
    
      <xsl:variable name="vKeyedElements" select=
       "key('kDByClass', $vKeyedValues)"/>
    
      <xsl:variable name="vNonKeyedElements" select=
      "//*[not(count(.|$vKeyedElements) = count($vKeyedElements))]
      "/>
    
     <xsl:template match="/">
      <xsl:for-each select="$vNonKeyedElements">
        Not Keyed: <xsl:value-of select="name()"/>
      </xsl:for-each>
     </xsl:template>
    
     <xsl:template match="text()"/>
    </xsl:stylesheet>
    

    when this transformation is applied on the same XML document (above), again the same, correct result is produced:

    Not Keyed: root
    Not Keyed: q
    

    Note: The last solution may not work when the key is not a node, but result of a function, such as substring-before(). In this case we simply modify the original key, so thet its use attribute is simply: use="." and use this solution with the modified original key. It can be prooven that this procedure produces the correct, wanted set of elements.

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