Question

I’m using this code to attempt to grab a table name and store it in a variable.

<?php
connectDB();
$sql = "SHOW TABLES";
$result = mysql_query($sql);
$tables = mysql_fetch_array($result);
    foreach ($tables as $table) {
        $table_name = $table[0];
        echo $table_name;
    }
closeConn();
?>

For one, its outputting ‘aa’ and ‘bb’ if i change the array index which i know arent table names in the db and two, what i want to do is run some code for every table in the db and insert the table name into a variable which i can use in said code? How would i do that?

Answer 1

$tables = mysql_fetch_array($result);

mysql_fetch_array fetches one row, not the entire set. This means that when you do $table[0], you are actually working on the string value of each field in the row.

You should put the mysql_fetch_array inside the loop instead:

while ($table = mysql_fetch_array($result)) {
    $table_name = $table[0];
    echo $table_name;
}