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Home/ Questions/Q 7547383
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T09:26:23+00:00 2026-05-30T09:26:23+00:00

I’m using this code to validate string. $countrecipient =’0123456789′; preg_match(‘/^[0]{1}[1]{1}[0-9]{1}[0-9]{7}?$/’, $countrecipient) How if I

  • 0

I’m using this code to validate string.

$countrecipient ='0123456789';

preg_match('/^[0]{1}[1]{1}[0-9]{1}[0-9]{7}?$/', $countrecipient)

How if I want to validate if the number contain “+” sign in front or not?

Such as :

$countrecipient ='+0123456789';

and still need to validate the rest of the string.

I tried this:

 if(preg_match('/^[+]{1}[6]{1}[0]{1}[1]{1}[0-9]{1}[0-9]{7}?$/', $countrecipient))
 {
   echo "Ok";
 }
 else
 {
   echo "Error";
 }

It works in my pc but I’m not sure why my customer is complaining it shows him error.

Thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-30T09:26:24+00:00Added an answer on May 30, 2026 at 9:26 am

    For an optional plus in front you could use:

    preg_match('/^\+?[0]{1}[1]{1}[0-9]{1}[0-9]{7}?$/', $countrecipient);
    

    Notice how I have escaped the + with a backslash? This is because it is a regex keyword which means 1 instance or more.

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