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Home/ Questions/Q 8088235
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T19:01:36+00:00 2026-06-05T19:01:36+00:00

I’m using this to (try) to validate a ‘strong’ password in ColdFusion 7. if

  • 0

I’m using this to (try) to validate a ‘strong’ password in ColdFusion 7.

if ( REFind("^(?=.*[A-Z])(?=.*[!@##$&*])(?=.*[0-9])(?=.*[a-z]).{6}$", myPassword, 1) EQ 0 )

However, it is failing. Can someone point out my error?

The criteria I think I’m testing is:

  • 1 upper
  • 1 lower
  • 1 number
  • 1 special char
  • 6 digit min

Footnotes for non-CF people:

  • the double hash is to escape the CF hash;
  • ColdFusion uses Jakarta ORO 2.0.6 as its regex engine
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T19:01:37+00:00Added an answer on June 5, 2026 at 7:01 pm

    Ok, well the set of criteria you’re trying to test on are bad.

    For example, Pa$5word meets the criteria but is a bad choice, whilst my name |z NOT Fr£d is much stronger but fails (no numbers; different symbols).

    Ideally you should look for and existing password strength checker (although I’ve no idea if there are any existing/good ones out there).

    Anyhow, for a simple solution to what you’ve asked, that spells out exactly what is being checked, just do:

    <cfif NOT 
        ( len(myPassword) GTE 6
        AND refind('[A-Z]',myPassword)
        AND refind('[a-z]',myPassword)
        AND refind('[0-9]',myPassword)
        AND refind('[!@##$&*]',myPassword)
         )>
    

    There is no need/benefit to smushing it all into a single regex.

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