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Home/ Questions/Q 3594924
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T19:46:59+00:00 2026-05-18T19:46:59+00:00

I’m using this tutorial as the basis for a Code Igniter / Doctrine based

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I’m using this tutorial as the basis for a Code Igniter / Doctrine based project.

http://www.phpandstuff.com/articles/codeigniter-doctrine-scratch-day-3-user-signup-form

Instead of using the code as-is for the models, my project is using a YAML schema file to generate the models

I’ve hit a snag, in that I’ve got no idea how to represent the following using YAML:

$this->hasMutator('password', '_encrypt_password');

(this is from the User model code, under ‘Adding Mutators’)
Specifically, I’m having trouble with the $this->hasMutator line

I’ve googled until blue, searched documentation for Doctrine, symfony (which I know uses Doctrine heavily) and even grep’d the codebase for references to mutators – I’ve come up empty

Is there a way to represent the line $this->hasMutator(‘password’, ‘_encrypt_password’); using Doctrine YAML?

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  1. Editorial Team
    Editorial Team
    2026-05-18T19:47:00+00:00Added an answer on May 18, 2026 at 7:47 pm

    (Just a note to clarify: we are talking about Doctrine 1.x here and not Doctrine 2.x)
    No, there is no a way to define mutators directly in your YAML schema. Are you sure you must register the mutator there?

    You could get around this limitation by creating you own doctrine behavior. Doctrine behaviors can be assigned to your models in the YAML schema. Read more here:

    http://www.doctrine-project.org/projects/orm/1.2/docs/manual/behaviors/pl

    In your case the behavior would look something like this:

    class EbonhandsTemplate extends Doctrine_Template
    {
        public function setUp()
        {
            $this->hasMutator('password', '_encrypt_password');
        }
    
        public function _encrypt_password
        ....
    }
    

    And in your yaml schema:

    EbonhandsModel:
      actAs: [EbonhandsTemplate]
    
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