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Home/ Questions/Q 6730143
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:22:21+00:00 2026-05-26T10:22:21+00:00

I’m using time() to store date in the database. I have some kind of

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I’m using time() to store date in the database.
I have some kind of advertising web site.
Users submit their ads and number of the days they want their ads to be shown for example:

title : ad title….

duration : 20 days

creation date : time() (I get the creation date by time() when I’m
submitting this ad on the database. )

I need to calculate expiration date for each ad on epoch format.

exp_date = creation date + 20 days ; /// this line is hypothetical , i need correct way to calculate exp_Date
sql->set(experation date = exp_date);

Also I need to know how much time is left to the exp date in days and hours and minutes and show it on the page.

    $current time = time();
    $remaining_time = $current time - $exp date ; //this line is hypothetical , i need correct way to calculate remaining_time
    echo 'remaining time : '.$remaining_time ;

At last I don’t want to show expired ads (I’m not sure the best way to do this is to calculate time when I’m showing the ads maybe I could somehow automatically disable ads status after 20 days?)

    current date = time();
    if (ads experation date > current date ) // this line is hypothetical , i need to calculate this 
    sql->update ('set ads status= 0');
    echo 'this ad has been expires ';
    exit;
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  1. Editorial Team
    Editorial Team
    2026-05-26T10:22:22+00:00Added an answer on May 26, 2026 at 10:22 am

    To calculate the expiration date:

    $expiration = time() + 1728000; // 1728000 = 20 * 24 * 60 * 60 (20 days)
    

    To calculate the time left, you should do something like

    $currentTime = time();
    $seconds = $expiration - $currentTime;
    
    $daysLeft = (int)($seconds / 86400); // 86400 = 24*60*60 (seconds in one day)
    $seconds -= $daysLeft * 86400;
    $hoursLeft = (int)($seconds / 3600); // 3600 = 60*60 (seconds in one hour)
    $seconds -= $hoursLeft * 3600;
    $minutesLeft = (int)($seconds / 60); // seconds in one minute
    $seconds -= $minutesLeft * 60;
    

    $daysLeft, $hoursLeft, $minutesLeft and $seconds are the values that you want

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