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Home/ Questions/Q 7884921
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:55:44+00:00 2026-06-03T04:55:44+00:00

I’m using Twitter bootstrap tooltips with javascript like the following: $(‘a[rel=tooltip]’).tooltip(); My markup looks

  • 0

I’m using Twitter bootstrap tooltips with javascript like the following:

$('a[rel=tooltip]').tooltip();

My markup looks like this:

<a rel="tooltip" title="Not implemented" class="btn"><i class="icon-file"></i></a>

This works fine, but I add <a> elements dynamically and the tooltips aren’t showing up for those dynamic elements. I know it’s because I only bind .tooltip() once when the document is finished loaded with the typical jquery $(document).ready(function() functionality.

How can I bind this to dynamically created elements? Usually I would do this via the jquery live() method. However, what is the event that I use to bind? I’m just not sure how to hook up the bootstrap .tooltip() with jquery .live().

I’ve found one way to make this work is something like this:

/* Add new 'rows' when plus sign is clicked */
$("a.add").live('click', function () {
    var clicked_li = $(this).parent('li');
    var clone = clicked_li.clone();

    clone.find(':input').each(function() {
        $(this).val('');
    });

    clicked_li.after(clone);
    $('a[rel=tooltip]').tooltip();
});

This works, but seems kind of hackish. I’m also calling the exact same .tooltip() line in the $(ready) call. So, do the elements that exist when the page first loads and match that selector end up with the tooltip twice?

I don’t see any problems with this approach. I’m just looking for a best practice or understanding of the behavior.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T04:55:46+00:00Added an answer on June 3, 2026 at 4:55 am

    Try this one:

    $('body').tooltip({
        selector: '[rel=tooltip]'
    });
    
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