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Home/ Questions/Q 6682195
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:40:40+00:00 2026-05-26T04:40:40+00:00

I’m using Umbraco 4.7.0 My goal is to get the image path from a

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I’m using Umbraco 4.7.0

My goal is to get the image path from a hard coded media node id of 4191. If I create a new macro with the code:

<xsl:copy-of select="umbraco.library:GetMedia(4191, false())"/>

I get the output:

/media/17675/my image.jpg50033618497jpg

I was expecting some well formed xml, however, it appears I’m missing all the tags. I therefore cannot reference the path for the image directly.

Am I missing something really simple here?

EDIT

I discovered how to get the raw xml output from my copy-of statement. I needed to wrap it in a <textarea> tag:

  <textarea>
      <xsl:copy-of select="umbraco.library:GetMedia(4191, false())"/>
  </textarea>
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  1. Editorial Team
    Editorial Team
    2026-05-26T04:40:40+00:00Added an answer on May 26, 2026 at 4:40 am

    This should do it:

    <xsl:copy-of select="umbraco.library:GetMedia(4191, 0)/umbracoFile"/>
    

    See also http://our.umbraco.org/wiki/reference/umbracolibrary/getmedia

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