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Home/ Questions/Q 7029255
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:30:53+00:00 2026-05-28T00:30:53+00:00

I’m using XmlReader to validate Xml against Xsd. When I validate this xml <?xml

  • 0

I’m using XmlReader to validate Xml against Xsd.

When I validate this xml

<?xml version="1.0" encoding="utf-8" ?>
<A><B>sdf</B></A>

against this schema:

<?xml version="1.0" encoding="utf-8"?>
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">

<xs:element name="B" type="xs:string" />

<xs:element name="A">
    <xs:complexType>
        <xs:sequence>
            <xs:element ref="B"/>
        </xs:sequence>
    </xs:complexType>
</xs:element>

</xs:schema>

validation is OK.

But if I add namespace:

<?xml version="1.0" encoding="utf-8" ?>
<A xmlns="myns"><B>sdf</B></A>

and corresponding schema:

<?xml version="1.0" encoding="utf-8"?>
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="myns">

<xs:element name="B" type="xs:string" />

<xs:element name="A">
    <xs:complexType>
        <xs:sequence>
            <xs:element ref="B"/>
        </xs:sequence>
    </xs:complexType>
</xs:element>

</xs:schema>

I accept System.Xml.Schema.XmlSchemaValidationException: The ‘B’ element is not declared.
Why this happens? And how can I add a namespace?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:30:54+00:00Added an answer on May 28, 2026 at 12:30 am

    The reason you are getting the validation error is that your schema is actually two schemas. You have two root elements, A and B. A root element cannot be implicitly used as a type. You need to tell XSD that you want to use types from another schema (using an import), or make those types local to the schema (using a complexType definition).

    Example: extract B out into it’s own schema. It cannot share the same namespace:

    <?xml version="1.0" encoding="utf-8"?>
    <xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="myns2">
      <xs:element name="B" type="xs:string" />
    </xs:schema>
    

    Then you can reference B from your A type by using import:

    <?xml version="1.0" encoding="utf-8"?>
    <xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="myns" xmlns:myns2="myns2">
    
      <xs:import namespace="myns2" />
    
      <xs:element name="A">
        <xs:complexType>
          <xs:sequence>
            <xs:element ref="myns2:B" />
          </xs:sequence>
        </xs:complexType>
      </xs:element>
    </xs:schema>
    

    This allows you to have the following valid XML instance:

    <?xml version="1.0" encoding="utf-8" ?>
    <A xmlns="myns">
      <B xmlns="myns2">sdf</B>
    </A>
    

    The reason you were able to validate the non-namespace’d versions of the types was because in order to be valid XML two things need to be true:

    • Well formed XML
    • Must conform to any referenced schema types

    In the non-namespace’d XML file, there is by definition no reference to any schema types, so therefore the document is valid XML.

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